3x^2-29x+56=12

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Solution for 3x^2-29x+56=12 equation:



3x^2-29x+56=12
We move all terms to the left:
3x^2-29x+56-(12)=0
We add all the numbers together, and all the variables
3x^2-29x+44=0
a = 3; b = -29; c = +44;
Δ = b2-4ac
Δ = -292-4·3·44
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{313}}{2*3}=\frac{29-\sqrt{313}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{313}}{2*3}=\frac{29+\sqrt{313}}{6} $

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